Unsafe operations
As we have previously explained, the
operation Now we will show how this can lead to not being actually closed due to anomalies.
We have to prove that
where
where
.
The computation goes as follows. Consider the evaluation of
on a vector
; the antifield expansion in the vicinity of
is:
Terms
of the higher order in
do not matter.
In passing from Line (44) to Line (45) we used the fact that
is non-anomalous, in other words
. In passing from Line (45) to Line (46) we used that
is non-anomalous
in the sense that
. The assumption that
is non-anomalous is quite reasonable, in fact
necessary for the consistency of the theory. But the ground for assuming
is much less solid. One possibility is to require:
which is more or less equivalent to:
It is quite possible that there are other possible ways to make calculations
meaningful, without imposing the ugly constraint (47).