Cohomology of
vs Lie algebra cohomology
In this Section we will show that the Modified de Rham complex of
is the same as the Lie algebra cohomology complex of
with coefficients in
.
1 Definition of the Lie algebra cohomology 
The space
is a representation of
; the action of
is slightly easier
to write down at the level of the corresponding action of the Lie group
;
acts on
as follows:
Therefore:
To follow the Faddeev-Popov notations, we introduce
| |||||||||||
|
| ||||||||||
Beware that
is not just the Faddeev-Popov ghost; it is the product of the Faddeev-Popov ghost
with
.
where
is the structure constants of
:
The subgroup
preserves
and therefore
:
This implies:
2 Proof that
is the same as 
This is similar to the statement that for any Lie group
, the de Rham subcomplex of right-invariant forms on
is the same as the Lie cohomology complex of
with coefficients in the trivial representation:
Our case is a variation on this theme:
As we explained,
consists of functions of
and
. To obtain the corresponding element
of
, we replace
with
with
(as in Eq. (15)), and
with
.
Under this identification
becomes
.