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1 Definition of the Lie algebra cohomology
2 Proof that is the same as

Cohomology of vs Lie algebra cohomology

In this Section we will show that the Modified de Rham complex of is the same as the Lie algebra cohomology complex of with coefficients in .

    1 Definition of the Lie algebra cohomology

    2 Proof that is the same as

1 Definition of the Lie algebra cohomology

The space is a representation of ; the action of is slightly easier to write down at the level of the corresponding action of the Lie group ; acts on as follows:

Therefore:

(12)

where is defined as in Eq. (2). We define to coincide with of Eq. (6):

(13)

To follow the Faddeev-Popov notations, we introduce

the Faddeev-Popov ghost:

(14)

then

  (cp. Eq. (2))

(15)

Beware that is not just the Faddeev-Popov ghost; it is the product of the Faddeev-Popov ghost with .

Eqs. (14) and (15) are equivalent to saying:

where is the structure constants of :

It is straightforward to verify using Eqs. (12) and (13) that:

The subgroup preserves and therefore :

This implies:

2 Proof that is the same as

This is similar to the statement that for any Lie group , the de Rham subcomplex of right-invariant forms on is the same as the Lie cohomology complex of with coefficients in the trivial representation:

Our case is a variation on this theme:

As we explained, consists of functions of and . To obtain the corresponding element of , we replace with with (as in Eq. (15)), and with . Under this identification becomes .