Descent to the moduli space of Lagrangian submanifolds
Let us interpret

as a PDF on

using the formula:
where

means factor over the symmetry:
For the descend to work,

should be base,
i.e. both invariant and
horizonthal, with respect to (
14). Actually, it is invariant and
almost horizonthal. The invariance is straightforward. Let us study
the question of horizonthality, and understand why it is “almost horizonthal”
instead of “horizonthal”. Let

denote a Hamiltonian
whose flux preserves the Lagrangian submanifold

. The horizonthality would
be equivalent to the statement that

is zero. But in fact,
Eq. (
13) implies:
Notice that

implies

.
Apriori this only
implies that

is a constant (but not necessarily zero).
This is potentially a problem (we certainly do want
to descend on
).
We will now outline possible ways of resolving this problem:
1 Use
instead of 
is naturally well-defined on the space of
Legendrian submanifolds in some contact submanifold
which is a
bundle over 
2 Use ghost number symmetry
There is usually a

symmetry called
ghost number. Let us do the following:
This eliminates the possibility of adding a constant to

and therefore
renders

unambigously defined from the variation of

. Our form

is now horizonthal, and descends from

to

.
3 Use transverse Lagrangian submanifold
Suppose that we can find a Lagrangian submanifold

which is transverse to all
Lagrangian submanifolds from our family:
where

is a
marked point on every

.
This eliminates the ambiguity of a constant in

.
What happens if we change

to another transversal Lagrangian submanifold

?
Let us assume that we can choose:
Then we just have to change:
As

is invariant, this would not change the result of the integration.
4 Upgrade
to 
The most elegant solution is to use, instead of the space of Lagrangian submanifolds

,
the space

of Lagrangian submanifolds with marked point. A point of

is a pair

where

and

. This defines the double fibration:
Given

, we can consider two projections

and

. Our

is a pseudo-differential form,
i.e. a function of

. We will define it so that it will depend on

only through

.
We can characterize

as a section of

modulo

. We then define

as
follows:
In order to make sense of

we must think of

as a section of

; the fact
that it is only defined up to tangent to

does not matter because

is isotropic. Eq. (
17)
eliminates the ambiguity, and we can now
safely define 
:
For every function

on

and for any PDF

on

, consider
the product

where:
We will now prove the following formula:
For small deformations of

we can always find canonical transformations

such that:
The introduction of such

is essentially a trick. It does not participate in any way
in the
definition of

; we will use it just to compute

.
We can now use the
moment map

.
We observe that:
—
the subtruction of

is needed to satisfy Eq. (
17).
Therefore:
Using Eq. (
3) with

:
and the fact that

we get:
But we also have to evaluate the exterior derivative of the prefactor:
This concludes the proof of Eq. (
18).
5 Classifying the possible ambiguities
Constant local or multilocal functionals are somewhat rare. As an example of such a functional,
consider
in the Yang-Mills theory on a compact four-manifold.
In the context of string theory, there are no local constant functionals if the target space
has sufficiently trivial topology.
6 Conclusion
Possible anomalies which could prevent the descent of

from

to

should be analized on the case-by-case basis.